History talk:Bonus Disc

One thing I'm not entirely sure about is how to handle expanded releases which have had their titles changed. Eg, Tri Repetae was also released as Tri Repetae++ 1) & (disc 2). I think we should represent the "++" despite the fact it seemingly only indicates the presence of the bonus disc. I propose renaming the discs to Tri Repetae++ and Tri Repetae++ (bonus disc) respectively. However since things like "Special Edition" are dropped, perhaps we should drop these too? --Gecks

• I think the key point is whether the original disc is avaliable with or without the second disc (or third..etc), If the disc is available with all versions, use "disc #" and if there are releases available without the release use "bonus disc". For Tri Repetae++ I would say "disc 2" applies as the ++ edition is not available without that 2nd disc -- drsaunde That's pretty much what I'm trying to change the guideline from :) it seems wrong to use (bonus disc) differently just because the album title changes (to reflect that it's packaged with a bonus disc, no less), or bonus tracks are present on the album disc. with this update i am trying to make the distinction between true multi-disc releases (eg, beatles - the white album), and reissues of single disc (or multi-disc) albums with extra bonus discs. -- Gecks
  • If Tri Repetae++ is always released as a 2-disc set, I'd use disc 1 and disc 2. And of course have bothe an entry for the 'first' disc as Tri Repetae++ and Tri Repetae. SO exactly as it is in the database at this moment (2007-09-18 18:09 GMT+1) --Zout
    • Again, the fact that it is always available as a 2-disc set does not alone mean it should be (disc 1) and (disc 2), according to the proposal. Tri Repetae is a single disc album - Tri Repetae++ is the name given to a version packaged with a (bonus disc). How to deal with this I think is unclear, but certainly according to the proposal there would not be a (disc 1) and (disc 2), only one or two versions of the album, and one version of the (bonus disc), as per my first comment. --Gecks